GCSE Revision

Series and parallel circuits

P2 equations

Series circuits

In a series circuit, the components are joined end to end in one loop.

  • is the same through every component.
  • The from the supply is shared between the components.
  • The is the sum of the resistances: R = R₁ + R₂
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Example: a 2 Ω and a 4 Ω resistor are in series with a 12 V supply.

  1. R = 2 + 4 = 6 Ω
  2. I = V ÷ R = 12 ÷ 6 = 2 A through both
  3. pd across 2 Ω = IR = 2 × 2 = 4 V
  4. pd across 4 Ω = IR = 2 × 4 = 8 V

Check: 4 V + 8 V = 12 V, the supply pd.

Key terms

Parallel circuits

In a parallel circuit, each component is on its own .

  • The across each branch is the same as the supply pd.
  • The is the sum of the currents in the branches.
  • The is less than the smallest resistance on its own.
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Example: a 6 Ω and a 3 Ω resistor are in parallel with a 6 V supply.

  1. Current through 6 Ω: I = 6 ÷ 6 = 1 A
  2. Current through 3 Ω: I = 6 ÷ 3 = 2 A
  3. Total current = 1 + 2 = 3 A
  4. Total resistance = 6 ÷ 3 = 2 Ω, less than 3 Ω

Key terms

Why parallel resistors lower the total

Adding a resistor in series makes the current pass through one more obstacle, so the total resistance goes up.

Adding a resistor in parallel gives the current an extra path. The pd across each branch stays the same, so the new branch carries its own current on top of the others. The supply now pushes for the same pd, so the .

Think of the checkouts in a shop: opening another till lets more people through at once, even if the new till is slow.

Exam tip

You won't be asked to calculate the total resistance of parallel resistors, but you must explain why it is lower.