GCSE Revision

Electrical power and energy

P2 equations

Electrical power

The of an appliance is the energy it transfers each second, in . You must recall both equations:

, or P = VI

, or P = I²R

QuantitySymbolUnit
PowerPwatts (W)
Potential differenceVvolts (V)
CurrentIamps (A)
ResistanceRohms (Ω)

Example 1: a 2300 W kettle runs on 230 V mains. Find the current.

  1. Rearrange: I = P ÷ V
  2. I = 2300 ÷ 230 = 10 A

Example 2: a current of 2 A flows through a 50 Ω heater.

  1. P = I²R = 2² × 50
  2. P = 4 × 50 = 200 W

Common mistake

In P = I²R, square the first, then multiply by the resistance.

Key terms

Energy transferred by appliances

Appliances transfer energy from the mains or a battery. A hair dryer fills the store of its fan motor and the store of its heating element. The energy transferred depends on the appliance's and how long it is on.

You must recall both equations:

, or E = Pt

, or E = QV

QuantitySymbolUnit
Energy transferredEjoules (J)
PowerPwatts (W)
Timetseconds (s)
Charge flowQcoulombs (C)
Potential differenceVvolts (V)

Key terms

Using E = Pt and E = QV

Example 1: a 2000 W hair dryer is used for 5 minutes. How much energy does it transfer?

  1. Convert: 5 minutes = 300 s
  2. E = Pt = 2000 × 300
  3. E = 600 000 J (600 kJ)

Example 2: 30 C of charge flows through a 12 V battery. How much energy is transferred?

  1. E = QV
  2. E = 30 × 12
  3. E = 360 J

Exam tip

Convert time to seconds first. For the hair dryer, t is 300 s, not 5.