Electrical power and energy
Electrical power
The of an appliance is the energy it transfers each second, in . You must recall both equations:
, or P = VI
, or P = I²R
| Quantity | Symbol | Unit |
|---|---|---|
| Power | P | watts (W) |
| Potential difference | V | volts (V) |
| Current | I | amps (A) |
| Resistance | R | ohms (Ω) |
Example 1: a 2300 W kettle runs on 230 V mains. Find the current.
- Rearrange: I = P ÷ V
- I = 2300 ÷ 230 = 10 A
Example 2: a current of 2 A flows through a 50 Ω heater.
- P = I²R = 2² × 50
- P = 4 × 50 = 200 W
Common mistake
In P = I²R, square the first, then multiply by the resistance.
Key terms
Energy transferred by appliances
Appliances transfer energy from the mains or a battery. A hair dryer fills the store of its fan motor and the store of its heating element. The energy transferred depends on the appliance's and how long it is on.
You must recall both equations:
, or E = Pt
, or E = QV
| Quantity | Symbol | Unit |
|---|---|---|
| Energy transferred | E | joules (J) |
| Power | P | watts (W) |
| Time | t | seconds (s) |
| Charge flow | Q | coulombs (C) |
| Potential difference | V | volts (V) |
Key terms
Using E = Pt and E = QV
Example 1: a 2000 W hair dryer is used for 5 minutes. How much energy does it transfer?
- Convert: 5 minutes = 300 s
- E = Pt = 2000 × 300
- E = 600 000 J (600 kJ)
Example 2: 30 C of charge flows through a 12 V battery. How much energy is transferred?
- E = QV
- E = 30 × 12
- E = 360 J
Exam tip
Convert time to seconds first. For the hair dryer, t is 300 s, not 5.