GCSE Revision

Current, resistance and potential difference

P2 equations

Resistance and V = IR

is how much a component opposes the flow of current. The current through a component depends on both the across it and its resistance. A bigger pd pushes more current; a bigger resistance lets less through.

You must recall this equation:

potential difference = current × resistance, or V = IR

QuantitySymbolUnit
Potential differenceVvolts (V)
CurrentIamps (A)
ResistanceRohms (Ω)

Example: a 6 Ω resistor has a pd of 12 V across it. Find the current.

  1. Rearrange: I = V ÷ R
  2. I = 12 ÷ 6
  3. I = 2 A

Key terms

Required practical 3: method

This practical shows how the length of a wire affects its resistance.

  1. Tape a length of thin constantan wire along a metre ruler.
  2. Connect it in series with a cell and an , using crocodile clips. Connect a across the wire between the clips.
  3. Set the clips 10 cm apart. Switch on, record the current and pd, then switch off.
  4. Calculate the resistance with R = V ÷ I.
  5. Repeat every 10 cm up to 100 cm.

The circuit, with the test wire drawn as a resistor:

AammeterresistorVvoltmetercell

Plot . You get a straight line: resistance is to length, so doubling the length doubles the resistance.

The same circuit can test resistors joined in series and in parallel.

Key terms

Required practical 3: variables, safety and accuracy

  • the length of the wire.
  • the resistance of the wire (worked out from V and I).
  • the material and thickness of the wire, and its temperature.

Hazard: the wire can get hot enough to burn you, so use a low pd and don't touch it while the current is on.

Improving accuracy: switch off between readings so the wire doesn't heat up, because a hotter wire has a higher resistance. Measure the length from the inside edges of the clips, and repeat each reading to find a mean.

Exam tip

If a question asks why the line doesn't pass exactly through zero, the clips and leads add a small resistance of their own.