Tree diagrams
Tree diagrams
A shows two or more events, one after the other. Events are if one doesn't affect the other, such as two spins of a spinner.
- Each set of branches from one point adds up to 1.
- Multiply along the branches for "this and then that".
- Add the results when more than one route gives what you want.
Example: P(red) = 0.3 on a spinner. It is spun twice. Find P(both red) and P(exactly one red).
- First spin: red 0.3, not red 0.7
- After red: red 0.3, not red 0.7
- After not red: red 0.3, not red 0.7
- P(both red) = 0.3 × 0.3 = 0.09
- Exactly one red: red then not red, or not red then red
- 0.3 × 0.7 + 0.7 × 0.3 = 0.21 + 0.21 = 0.42
Key terms
At least one
"At least one" means one or more. It's quickest to work out the opposite, "none", and subtract from 1.
P(at least one) = 1 − P(none)
Example: the spinner with P(red) = 0.3 is spun twice. Find P(at least one red).
- P(no reds) = 0.7 × 0.7 = 0.49
- P(at least one red) = 1 − 0.49 = 0.51
Check: P(both red) + P(exactly one red) = 0.09 + 0.42 = 0.51.
Exam tip
All the end results of a tree diagram add up to 1: 0.09 + 0.21 + 0.21 + 0.49 = 1. Use this to check your branches.
Without replacement (Higher tier only)
If an item isn't put back, the second probabilities change: there is one fewer item, and maybe one fewer of that colour. These are events.
Example: a bag has 5 red and 3 blue counters. Two are taken without replacement. Find P(both red) and P(one of each colour).
- First: red 5/8, blue 3/8
- After red: red 4/7, blue 3/7
- After blue: red 5/7, blue 2/7
- P(both red) = 5/8 × 4/7 = 20/56 = 5/14
- Red then blue: 5/8 × 3/7 = 15/56
- Blue then red: 3/8 × 5/7 = 15/56
- P(one of each) = 30/56 = 15/28